#include <bits/stdc++.h> using namespace std; int main(){ int x,y; cin>>x>>y; cout<<x<<"+"<<y<<"="<<(x+y)<<endl; cout<<x<<"-"<<y<<"="<<(x-y)<<endl; cout<<x<<""<<y<<"="<<(xy)<<endl; cout<<x<<"/"<<y<<"="<<(x/y)<<"..."<<(x%y)<<endl; return 0; }

其实这道题非常简单

#include <bits/stdc++.h>
using namespace std;
int main(){
	int a,b,c;
	cin>>a>>b>>c;
	if(a+b>c && b+c>a && a+c>b){
		cout<<"yes";
	}
	else{
		cout<<"no";
	}
	return 0;
}

6

#include <bits/stdc++.h> using namespace std; int main(){ int a,b,c; cin>>a>>b>>c; if(a+b>c && b+c>a && a+c>b){ cout<<"yes"; } else{ cout<<"no"; } return 0; }