1 条题解
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0
#include <iostream> #include <string> using namespace std; int main() { string shitou = "Rock"; string jiandao = "Scissors"; string bu = "Paper"; int N; cin >> N; for (int i = 0; i < N; ++i) { string s1, s2; cin >> s1 >> s2; if (s1 == s2) { cout << "Tie" << endl; } else if ((s1 == shitou && s2 == jiandao) || (s1 == jiandao && s2 == bu) || (s1 == bu && s2 == shitou)) { cout << "Player1" << endl; } else { cout << "Player2" << endl; } } return 0; }
- 1
信息
- ID
- 608
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- (无)
- 递交数
- 1
- 已通过
- 1
- 上传者