1 条题解

  • 0
    @ 2025-4-9 13:17:35
    #include <iostream>
    #include <string>
    using namespace std;
    int main() {
        string shitou = "Rock";
        string jiandao = "Scissors";
        string bu = "Paper";
        int N;
        cin >> N;
        for (int i = 0; i < N; ++i) {
            string s1, s2;
            cin >> s1 >> s2;
            if (s1 == s2) {
                cout << "Tie" << endl;
            }
            else if ((s1 == shitou && s2 == jiandao) ||
                     (s1 == jiandao && s2 == bu) ||
                     (s1 == bu && s2 == shitou)) {
                cout << "Player1" << endl;
            }
            else {
                cout << "Player2" << endl;
            }
        }
        return 0;
    }
  • 1

信息

ID
608
时间
1000ms
内存
256MiB
难度
10
标签
(无)
递交数
1
已通过
1
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