1 条题解
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1
#include <cstdio> #include <climits> int main() { int n; scanf("%d", &n); if (n < 2) { printf("0\n"); return 0; } int min_val; scanf("%d", &min_val); int max_diff = INT_MIN; for (int i = 1; i < n; ++i) { int current; scanf("%d", ¤t); int diff = current - min_val; if (diff > max_diff) { max_diff = diff; } if (current < min_val) { min_val = current; } } if (max_diff < 0) { max_diff = 0; } printf("%d\n", max_diff); return 0; }
- 1
信息
- ID
- 503
- 时间
- 100ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 2
- 已通过
- 2
- 上传者