高精度

#include <bits/stdc++.h>
using namespace std;

string s1, s2;
int arr[2000], brr[2000], crr[4007];

int main()
{
	cin >> s1 >> s2;
	int len1 = s1.size() - 1;
	int len2 = s2.size() - 1;

	
	for (int i = 0; i <= len1; i++) arr[len1 - i] = s1[i] - '0';
	
	for (int i = 0; i <= len2; i++) brr[len2 - i] = s2[i] - '0';

	return 0;
	
}